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Does anyone know how to calculate a Mod b in Casio fx-991ES Calculator. Thanks
user1035927user103592710 Answers
This calculator does not have any modulo function. However there is quite simple way how to compute modulo using display mode ab/c
(instead of traditional d/c
).
How to switch display mode to ab/c
:
- Go to settings (Shift + Mode).
- Press arrow down (to view more settings).
- Select
ab/c
(number 1).
Now do your calculation (in comp mode), like 50 / 3
and you will see 16 2/3
, thus, mod is 2
. Or try 54 / 7
which is 7 5/7
(mod is 5
).If you don't see any fraction then the mod is 0
like 50 / 5 = 10
(mod is 0
).
The remainder fraction is shown in reduced form, so 60 / 8
will result in 7 1/2
. Remainder is 1/2
which is 4/8
so mod is 4
.
EDIT:As @lawal correctly pointed out, this method is a little bit tricky for negative numbers because the sign of the result would be negative.
For example -121 / 26 = -4 17/26
, thus, mod is -17
which is +9
in mod 26. Alternatively you can add the modulo base to the computation for negative numbers: -121 / 26 + 26 = 21 9/26
(mod is 9
).
EDIT2: As @simpatico pointed out, this method will not work for numbers that are out of calculator's precision. If you want to compute say 200^5 mod 391
then some tricks from algebra are needed. For example, using rule(A * B) mod C = ((A mod C) * B) mod C
we can write:
200^5 mod 391 = (200^3 * 200^2) mod 391 = ((200^3 mod 391) * 200^2) mod 391 = 98

As far as I know, that calculator does not offer mod functions.You can however computer it by hand in a fairly straightforward manner.Ex.
(1)50 mod 3
(2)50/3 = 16.66666667
(3)16.66666667 - 16 = 0.66666667
(4)0.66666667 * 3 = 2
Therefore 50 mod 3 = 2
Magic recovery professional v3 2 full crack gratis. Things to Note:On line 3, we got the 'minus 16' by looking at the result from line (2) and ignoring everything after the decimal. The 3 in line (4) is the same 3 from line (1).
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Hope that Helped.
Edit As a result of some trials you may get x.99991 which you will then round up to the number x+1.
mbm29414There is a switch a^b/c
If you want to calculate
then enter 491 press a^b/c then enter 12. Then you will get 40, 11, 12. Here the middle one will be the answer that is 11.
Similarly if you want to calculate 41 mod 12
then find 41 a^b/c 12. You will get 3, 5, 12 and the answer is 5 (the middle one). The mod
is always the middle value.
You can calculate A mod B (for positive numbers) using this:
Pol( -Rec( 1/2πr , 2πr × A/B ) , Y ) ( πr - Y ) B
Then press [CALC], and enter your values for A and B, and any value for Y.
/ indicates using the fraction key, and r means radians ( [SHIFT] [Ans] [2] )
Mina MichaelYou need 10 ÷R 3 = 1This will display both the reminder and the quoitent
÷R
Mina Gabriel
Casio Fx 991 Es Plus Emulator For Pc
It all falls back to the definition of modulus: It is the remainder, for example, 7 mod 3 = 1.This because 7 = 3(2) + 1, in which 1 is the remainder.
To do this process on a simple calculator do the following:Take the dividend (7) and divide by the divisor (3), note the answer and discard all the decimals -> example 7/3 = 2.3333333, only worry about the 2. Now multiply this number by the divisor (3) and subtract the resulting number from the original dividend.
https://stelesitop.tistory.com/11. Clicking and holding the ViewCube allows the model to be freely roated in any direction.
so 2*3 = 6, and 7 - 6 = 1, thus 1 is 7mod3
Here's how I usually do it. For example, to calculate 1717 mod 2
:
- Take
1717 / 2
. The answer is 858.5 - Now take 858 and multiply it by the mod (
2
) to get1716
- Finally, subtract the original number (
1717
) minus the number you got from the previous step (1716
) --1717-1716=1
.
So 1717 mod 2
is 1
.
To sum this up all you have to do is multiply the numbers before the decimal point with the mod then subtract it from the original number.
type normal division first and then type shift + S->d
DilanGDilanGHow To Find Cramer Rule On Fx 991 Es Plus
Calculate x/y
(your actual numbers here), and press a b/c key, which is 3rd one below Shift key.
protected by maurisNov 11 '14 at 5:24
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